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Proof step 52 from proof exvalidrefs-maxlength (previous step)

¬ (junkrefs(str, (r0 ' + refs) + r ', ty, st -- r) ∧ ¬ junkref(str, r0, st) ∧ r ≠ r0 ∧ ¬ r ∈ refs ∧ st[r0 -- _type] .type ≤ ty), st[r -- _type] .type = mkclasstype(class0), st[r -- mkfs(class, ty, fieldvar) '] = refval(r0), st[r0 -- _type] .type ≤ ty, is_reftype(ty), mkfs(class, ty, fieldvar) ' ∈ instfields(class0), is_obj(str, r, st), is_obj(r, st), junkrefs(str, (r0 ' + refs) + r ', st[r0 -- _type] .type, st -- r), ∀ r, str, st0. # st0 .refs < # st .refs → ( true → cyclic(str, r, st0) ∨ junkref(str, r, st0) ∨ (∃ refs. validrefs(str, refs, st0[refs .first -- _type] .type, st0) ∧ refs ≠ [] ∧ ¬ dups(refs) ∧ refs .first = r ∧ ¬ has_reffield(refs .last, st0))) ⊦ r0 = jvmref, r = jvmref, r = r0, r ∈ refs, junkref(str, r0, st), validrefs(str, r0 ' + refs + r ', ty, st), ∃ refs. validrefs(str, refs, st[refs .first -- _type] .type, st) ∧ refs ≠ [] ∧ ¬ dups(refs) ∧ refs .first = r ∧ ¬ has_reffield(refs .last, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1])]]