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Proof step 6 from proof junkref-put-nopathex-equiv-01 (previous step)

is_valid_ref(str, r0, st), junkrefs(str, r ' + refs1, st[r -- _type] .type, st[r0 -- sk, val]) ⊦ sk = _type, path∃(str, r, r0, st), ∃ refs0. refs0 ≠ [] ∧ refs0 .first = r ∧ junkrefs(str, refs0, st[refs0 .first -- _type] .type, st)

User applied rule exists right

And obtained the following new goals

Proof step 5:
is_valid_ref(str, r0, st), junkrefs(str, r ' + refs1, st[r -- _type] .type, st[r0 -- sk, val]) ⊦ sk = _type, path∃(str, r, r0, st), r ' + refs1 ≠ [] ∧ (r ' + refs1) .first = r ∧ junkrefs(str, r ' + refs1, st[(r ' + refs1) .first -- _type] .type, st)

Rule argument

[EXRARG : pos: right 3, [extquanttermlist: (r ' + refs1) abort:F , discard:T , computed:F ]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r ' + refs1)]]