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Proof step 11 from proof junkref-put-nopathex (previous step)

junkref(str, r, st[r0 -- sk, val]) ⊦ sk = _type, path∃(str, r, r0, st), ∃ refs. refs ≠ [] ∧ refs .first = r ∧ junkrefs(str, refs, st[r -- _type] .type, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
junkref(str, r, st[r0 -- sk, val]) ⊦ sk = _type, path∃(str, r, r0, st), ∃ refs. refs ≠ [] ∧ refs .first = r ∧ junkrefs(str, refs, st[refs .first -- _type] .type, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]