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Proof step 23 from proof junkref-put-nopathexplus-equiv (conclusion)

⊦ ¬ path∃+(str, r, r0, st) ∧ sk ≠ _type → (junkref(str, r, st[r0 -- sk, val]) ↔ junkref(str, r, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 22:
⊦ sk = _type, junkref(str, r, st[r0 -- sk, val]) ↔ junkref(str, r, st), path∃+(str, r, r0, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]