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Proof step 11 from proof junkref-update (previous step)

fv = sk × val, junkref(str, r, update(r0, fis0, st)[r0 -- sk, val]), ∀ str0, r1, r2, st0. junkref(str0, r1, update(r2, fis0, st0)) → path∃(str0, r1, r2, st0) ∨ junkref(str0, r1, st0) ⊦ junkref(str, r, st), path∃(str, r, r0, st), _type ∈ fv ', _type ∈ fis0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
junkref(str, r, update(r0, fis0, st)[r0 -- sk, val]), ∀ str0, r1, r2, st0. junkref(str0, r1, update(r2, fis0, st0)) → path∃(str0, r1, r2, st0) ∨ junkref(str0, r1, st0) ⊦ _type = sk, _type ∈ fis0, junkref(str, r, st), path∃(str, r, r0, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ sk ∈ (sk0 × val) ' ↔ sk = sk0])]]