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Proof step 57 from proof junkrefs-put-nopathex (previous step)

(st[r0 -- sk, val][r1 -- i ']) = refval(r2), 0 ≤ i, 0 < (st[r0 -- sk, val][r1 -- _length]) .intval, is_array(str, r1, st[r0 -- sk, val]), st[r1 -- _type] .type ≤ ty, is_array(str, r1, st), i < (st[r0 -- sk, val][r1 -- _length]) .intval, is_referencevalue(st[r0 -- sk, val][r1 -- i ']), junkrefs(str, r2 ' + refs, st[r1 -- _type] .type .type, st[r0 -- sk, val]), ∀ str0, r, st0, ty0, sk0, val0. ¬ path∃(str0, r2, r, st0) ∧ ¬ junkrefs(str0, r2 ' + refs, ty0, st0) ∧ sk0 ≠ _type → ¬ junkrefs(str0, r2 ' + refs, ty0, st0[r -- sk0, val0]) ⊦ sk = _type, r1 = jvmref, path∃(str, r1, r0, st), junkrefs(str, r1 ' + r2 ' + refs, ty, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 56:
(st[r0 -- sk, val][r1 -- i ']) = refval(r2), junkrefs(str, r2 ' + refs, st[r1 -- _type] .type .type, st[r0 -- sk, val]), i < (st[r0 -- sk, val][r1 -- _length]) .intval, is_array(str, r1, st), st[r1 -- _type] .type ≤ ty, is_array(str, r1, st[r0 -- sk, val]), 0 < (st[r0 -- sk, val][r1 -- _length]) .intval, 0 ≤ i, ∀ str0, r, st0, ty0, sk0, val0. ¬ path∃(str0, r2, r, st0) ∧ ¬ junkrefs(str0, r2 ' + refs, ty0, st0) ∧ sk0 ≠ _type → ¬ junkrefs(str0, r2 ' + refs, ty0, st0[r -- sk0, val0]) ⊦ r1 = jvmref, sk = _type, junkrefs(str, r1 ' + r2 ' + refs, ty, st), path∃(str, r1, r0, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ is_referencevalue(refval(r))], [CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1])]]