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Proof step 60 from proof junkrefs-put-nopathex (previous step)

acc .first = (st[r0 -- sk, val][r1 -- i ']) .refval, is_array(str, r1, st[r0 -- sk, val]), st[r1 -- _type] .type ≤ ty, is_array(str, r1, st), i < (st[r0 -- sk, val][r1 -- _length]) .intval, is_referencevalue(st[r0 -- sk, val][r1 -- i ']), junkrefs(str, acc, st[r1 -- _type] .type .type, st[r0 -- sk, val]), 0 ≤ i, 0 < (st[r0 -- sk, val][r1 -- _length]) .intval, ∀ str0, r, st0, ty0, sk0, val0. ¬ path∃(str0, acc .first, r, st0) ∧ ¬ junkrefs(str0, acc, ty0, st0) ∧ sk0 ≠ _type → ¬ junkrefs(str0, acc, ty0, st0[r -- sk0, val0]) ⊦ sk = _type, r1 = jvmref, acc = [], junkrefs(str, r1 ' + acc, ty, st), path∃(str, r1, r0, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 59:
acc = r2 + refs, r2 = (st[r0 -- sk, val][r1 -- i ']) .refval, is_array(str, r1, st[r0 -- sk, val]), st[r1 -- _type] .type ≤ ty, is_array(str, r1, st), i < (st[r0 -- sk, val][r1 -- _length]) .intval, is_referencevalue(st[r0 -- sk, val][r1 -- i ']), junkrefs(str, acc, st[r1 -- _type] .type .type, st[r0 -- sk, val]), 0 ≤ i, 0 < (st[r0 -- sk, val][r1 -- _length]) .intval, ∀ str0, r, st0, ty0, sk0, val0. ¬ path∃(str0, r2, r, st0) ∧ ¬ junkrefs(str0, acc, ty0, st0) ∧ sk0 ≠ _type → ¬ junkrefs(str0, acc, ty0, st0[r -- sk0, val0]) ⊦ sk = _type, r1 = jvmref, acc = [], junkrefs(str, r1 ' + acc, ty, st), path∃(str, r1, r0, st)

Rule argument

[speclemmaarg: refs ≠ [] ,r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0 ,[refs, r, refs0] → [acc, r2, refs] ,T ,list-data ,references-olista ,elim-list-c ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : refs ≠ [] ⊦ r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0])], [EXTRATERMS : (acc, r2, refs)]]