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Proof step 119 from proof junkrefs-put-nopathexplus-equiv (previous step)

junkrefs(str, r ' + refs0, ty, st), ∀ val, sk, r0, st, ty, r, str, refs. # refs < # refs0 → (junkrefs(str, r ' + refs, ty, st) → junkrefs(str, r ' + refs, ty, st[r0 -- sk, val]) ∨ sk = _type ∨ path∃+(str, r, r0, st)) ⊦ r = jvmref, sk = _type, junkrefs(str, r ' + refs0, ty, st[r0 -- sk, val]), path∃+(str, r, r0, st)

User applied rule cut formula

And obtained the following new goals

Proof step 9:
r = r0, junkrefs(str, r ' + refs0, ty, st), ∀ val, sk, r0, st, ty, r, str, refs. # refs < # refs0 → (junkrefs(str, r ' + refs, ty, st) → junkrefs(str, r ' + refs, ty, st[r0 -- sk, val]) ∨ sk = _type ∨ path∃+(str, r, r0, st)) ⊦ r = jvmref, sk = _type, junkrefs(str, r ' + refs0, ty, st[r0 -- sk, val]), path∃+(str, r, r0, st)
Proof step 118:
junkrefs(str, r ' + refs0, ty, st), ∀ val, sk, r0, st, ty, r, str, refs. # refs < # refs0 → (junkrefs(str, r ' + refs, ty, st) → junkrefs(str, r ' + refs, ty, st[r0 -- sk, val]) ∨ sk = _type ∨ path∃+(str, r, r0, st)) ⊦ r = r0, r = jvmref, sk = _type, junkrefs(str, r ' + refs0, ty, st[r0 -- sk, val]), path∃+(str, r, r0, st)

Rule argument

[fma-arg: r = r0]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRAFMAS : (r = r0)]]