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Proof step 127 from proof junkrefs-put-nopathexplus-equiv (conclusion)

⊦ ¬ path∃+(str, r, r0, st) ∧ sk ≠ _type ∧ refs ≠ [] ∧ refs .first = r → (junkrefs(str, refs, ty, st[r0 -- sk, val]) ↔ junkrefs(str, refs, ty, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 126:
⊦ junkrefs(str, refs, ty, st[r0 -- sk, val]) ↔ junkrefs(str, refs, ty, st), refs = [], sk = _type, path∃+(str, refs .first, r0, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]