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Proof step 21 from proof pathex-class (previous step)

∃ refs. refs ≠ [] ∧ refs .first = r ∧ refs .last = r0 ∧ validrefs(str, refs, st[r -- _type] .type, st), is_obj(str, r, st) ⊦ ∃ fs. fs ' ∈ instfields(st[r -- _type] .type .class) ∧ is_referencevalue(st[r -- fs ']) ∧ ( st[r -- fs '] .refval ≠ jvmref ∧ st[st[r -- fs '] .refval -- _type] .type ≤ fs .type ∧ path∃(str, st[r -- fs '] .refval, r0, st) ∨ st[r -- fs '] .refval = jvmref ∧ r0 = jvmref), r = r0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
validrefs(str, refs, st[refs .first -- _type] .type, st), is_obj(str, refs .first, st) ⊦ refs .first = refs .last, refs = [], ∃ fs. fs ' ∈ instfields(st[refs .first -- _type] .type .class) ∧ is_referencevalue(st[refs .first -- fs ']) ∧ ( st[refs .first -- fs '] .refval ≠ jvmref ∧ st[st[refs .first -- fs '] .refval -- _type] .type ≤ fs .type ∧ path∃(str, st[refs .first -- fs '] .refval, refs .last, st) ∨ st[refs .first -- fs '] .refval = jvmref ∧ refs .last = jvmref)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]