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Proof step 52 from proof pathex-class (previous step)

is_obj(str, r, st), is_referencevalue(st[r -- fs ']), fs ' ∈ instfields(st[r -- _type] .type .class), st[r -- fs '] .refval ≠ jvmref ∧ st[st[r -- fs '] .refval -- _type] .type ≤ fs .type ∧ path∃(str, st[r -- fs '] .refval, r0, st) ∨ st[r -- fs '] .refval = jvmref ∧ r0 = jvmref ⊦ r = r0, path∃(str, r, r0, st)

User applied rule cut formula

And obtained the following new goals

Proof step 33:
st[r -- fs '] .refval = jvmref ∧ r0 = jvmref, is_obj(str, r, st), is_referencevalue(st[r -- fs ']), fs ' ∈ instfields(st[r -- _type] .type .class), st[r -- fs '] .refval ≠ jvmref ∧ st[st[r -- fs '] .refval -- _type] .type ≤ fs .type ∧ path∃(str, st[r -- fs '] .refval, r0, st) ∨ st[r -- fs '] .refval = jvmref ∧ r0 = jvmref ⊦ r = r0, path∃(str, r, r0, st)
Proof step 51:
is_obj(str, r, st), is_referencevalue(st[r -- fs ']), fs ' ∈ instfields(st[r -- _type] .type .class), st[r -- fs '] .refval ≠ jvmref ∧ st[st[r -- fs '] .refval -- _type] .type ≤ fs .type ∧ path∃(str, st[r -- fs '] .refval, r0, st) ∨ st[r -- fs '] .refval = jvmref ∧ r0 = jvmref ⊦ st[r -- fs '] .refval = jvmref ∧ r0 = jvmref, r = r0, path∃(str, r, r0, st)

Rule argument

[fma-arg: (st[r -- fs '] .refval = jvmref ∧ r0 = jvmref)]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRAFMAS : ((st[r -- fs '] .refval = jvmref ∧ r0 = jvmref))]]