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Proof step 2 from proof pathex-junkref-02 (conclusion)
⊦ path∃(str, r, r0, st) ∧ ¬ junkref(str, r, st) → ¬ junkref(str, r0, st)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 1
:
⊦ junkref(str, r0, st) ∧ ¬ junkref(str, r, st) → ¬ path∃(str, r, r0, st)
Rule argument
[emptyarg]
Additional information
[[CONCRETESIMPRULES : ()]]