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Proof step 10 from proof pathex-junkref (previous step)

validrefs(str, r ' + refs0, st[r -- _type] .type, st), ∃ refs. refs ≠ [] ∧ refs .first = refs0 .last ∧ junkrefs(str, refs, st[refs0 .last -- _type] .type, st) ⊦ refs0 = [], ∃ refs. refs ≠ [] ∧ refs .first = r ∧ junkrefs(str, refs, st[refs .first -- _type] .type, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
refs .first = refs0 .last, junkrefs(str, refs, st[refs0 .last -- _type] .type, st), validrefs(str, r ' + refs0, st[r -- _type] .type, st) ⊦ refs = [], refs0 = [], ∃ refs. refs ≠ [] ∧ refs .first = r ∧ junkrefs(str, refs, st[refs .first -- _type] .type, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]