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Proof step 17 from proof pathex-levelsubset-01 (previous step)

r ≠ r0, validref(str, r, ty, st), ∃ refs. refs ≠ [] ∧ refs .first = r ∧ refs .last = r0 ∧ ¬ dups(refs) ∧ validrefs(str0, refs, st[r -- _type] .type, st), level⊆(str, str0) ⊦ path∃(str, r, r0, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
validref(str, refs .first, ty, st), validrefs(str0, refs, st[refs .first -- _type] .type, st), level⊆(str, str0) ⊦ refs = [], refs .first = refs .last, path∃(str, refs .first, refs .last, st), dups(refs)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]