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Proof step 19 from proof pathex-levelsubset-01 (conclusion)

⊦ level⊆(str, str0) ∧ path∃(str0, r, r0, st) ∧ validref(str, r, ty, st) → path∃(str, r, r0, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
validref(str, r, ty, st), path∃(str0, r, r0, st), level⊆(str, str0) ⊦ path∃(str, r, r0, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]