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Proof step 6 from proof pathex-not-is-validref-01 (previous step)

∃ refs. refs ≠ [] ∧ refs .first = r ∧ refs .last = r1 ∧ validrefs(str, refs, st[r -- _type] .type, st) ⊦ r1 = jvmref, is_valid_ref(str, r1, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
validrefs(str, refs, st[refs .first -- _type] .type, st) ⊦ refs .last = jvmref, refs = [], is_valid_ref(str, refs .last, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]