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Proof step 18 from proof pathex-put-array-badindex (previous step)

i < 0 ⊦ (∃ refs. refs ≠ [] ∧ refs .first = r ∧ refs .last = r1 ∧ validrefs(str, refs, (st[r0 -- i ', val][r -- _type]) .type, st[r0 -- i ', val])) ↔ (∃ refs. refs ≠ [] ∧ refs .first = r ∧ refs .last = r1 ∧ validrefs(str, refs, st[refs .first -- _type] .type, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
i < 0 ⊦ (∃ refs. refs ≠ [] ∧ refs .first = r ∧ refs .last = r1 ∧ validrefs(str, refs, st[refs .first -- _type] .type, st[r0 -- i ', val])) ↔ (∃ refs. refs ≠ [] ∧ refs .first = r ∧ refs .last = r1 ∧ validrefs(str, refs, st[refs .first -- _type] .type, st))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : javastore, , type-at, ⊦ (st[r -- i ', val] [r0 -- _type ] ) = st[r0 -- _type]])]]