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Proof step 14 from proof pathex-put-last (previous step)

refs = r + refs0, validrefs(str, refs, st[r -- _type] .type, st[refs .last -- sk, val]) ⊦ sk = _type, refs = [], r = refs .last, path∃(str, r, refs .last, st), junkref(str, r, st), dups(refs)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
validrefs(str, r ' + refs0, st[r -- _type] .type, st[(r ' + refs0) .last -- sk, val]) ⊦ sk = _type, r = (r ' + refs0) .last, path∃(str, r, (r ' + refs0) .last, st), junkref(str, r, st), dups(refs0), r ∈ refs0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ dups(r ' + refs) ↔ dups(refs) ∨ r ∈ refs], [CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ r ' + refs ≠ []], [CSIMPSEQ : ⊦ r + refs = r ' + refs])]]