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Proof step 8 from proof pathex-put-last (previous step)

r ≠ r0, validrefs(str, r ' + refs1 + r0 ', st[r -- _type] .type, st[r0 -- sk, val]) ⊦ r = r0, sk = _type, r ∈ refs1, dups(refs1), r0 ∈ refs1, junkref(str, r, st), ∃ refs. refs ≠ [] ∧ refs .first = r ∧ refs .last = r0 ∧ ¬ dups(refs) ∧ validrefs(str, refs, st[r -- _type] .type, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
validrefs(str, r ' + refs1 + r0 ', st[r -- _type] .type, st[r0 -- sk, val]) ⊦ sk = _type, r = r0, r ∈ refs1, dups(refs1), r0 ∈ refs1, junkref(str, r, st), ∃ refs. refs ≠ [] ∧ refs .first = r ∧ refs .last = r0 ∧ ¬ dups(refs) ∧ validrefs(str, refs, st[refs .first -- _type] .type, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]