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Proof step 199 from proof pathex-put-nopathex (previous step)

is_array(str, r, st), refs0 = [] ∨ 0 ≤ i ∧ i < st[r -- _length] .intval ∧ is_referencevalue(st[r -- i ']) ∧ refs0 .first = st[r -- i '] .refval ∧ validrefs(str, refs0, st[r -- _type] .type .type, st), ∀ val, r0, sk, st, r, str, refs. # refs < # refs0 → ( validrefs(str, r ' + refs, st[r -- _type] .type, st) → sk = _type ∨ path∃(str, r, r0, st) ∨ junkref(str, r, st) ∨ path∃(str, r, (r ' + refs) .last, st[r0 -- sk, val])) ⊦ sk = _type, r = jvmref, path∃(str, r, (r ' + refs0) .last, st[r0 -- sk, val]), junkref(str, r, st), path∃(str, r, r0, st)

User applied rule cut formula

And obtained the following new goals

Rule argument

[fma-arg: refs0 = []]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRAFMAS : (refs0 = [])]]