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Proof step 215 from proof pathex-put-nopathex (previous step)

⊦ sk = _type, path∃(str, r, r1, st[r0 -- sk, val]) ↔ path∃(str, r, r1, st), path∃(str, r, r0, st), junkref(str, r, st)

User applied rule case distinction

And obtained the following new goals

Rule argument

[CASEDARG : pos: right 2, ()]

Additional information

[[CONCRETESIMPRULES : ()]]