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Proof step 84 from proof pathex-put-nopathex (previous step)

refs0 .first = (st[r0 -- sk, val][r -- i ']) .refval, is_array(str, r, st[r0 -- sk, val]), i < (st[r0 -- sk, val][r -- _length]) .intval, is_referencevalue(st[r0 -- sk, val][r -- i ']), validrefs(str, refs0, st[r -- _type] .type .type, st[r0 -- sk, val]), 0 ≤ i, 0 < (st[r0 -- sk, val][r -- _length]) .intval, ∀ val, sk, r0, st, r, str, refs. # refs < # refs0 → ( validrefs(str, r ' + refs, st[r -- _type] .type, st[r0 -- sk, val]) → sk = _type ∨ path∃(str, r, r0, st) ∨ junkref(str, r, st) ∨ path∃(str, r, (r ' + refs) .last, st)) ⊦ sk = _type, r = jvmref, refs0 = [], junkref(str, r, st), path∃(str, r, r0, st), path∃(str, r, refs0 .last, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

[speclemmaarg: refs ≠ [] ,r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0 ,[refs, r, refs0] → [refs0, r1, refs1] ,T ,list-data ,references-olista ,elim-list-c ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : refs ≠ [] ⊦ r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0])], [EXTRATERMS : (refs0, r1, refs1)]]