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Proof step 10 from proof pathex-putbar (previous step)

∀ r2, st, str, r, r1, i. okbytearray(r2, st) → (path∃(str, r, r1, putByteArray(bytes0, r2, i, st)) ↔ path∃(str, r, r1, st)), okbytearray(r2, st) ⊦ path∃(str, r, r1, putByteArray(by + bytes0, r2, i, st)) ↔ path∃(str, r, r1, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
okbytearray(r2, st), ∀ r2, st, str, r, r1, i. okbytearray(r2, st) → (path∃(str, r, r1, putByteArray(bytes0, r2, i, st)) ↔ path∃(str, r, r1, st)) ⊦ path∃(str, r, r1, putByteArray(by ' + bytes0, r2, i, st)) ↔ path∃(str, r, r1, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : list, bytelist, c, ⊦ by + bytes = by ' + bytes])]]