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Proof step 12 from proof pathex-putbar (conclusion)

⊦ okbytearray(r2, st) → (path∃(str, r, r1, putByteArray(bytes, r2, i, st)) ↔ path∃(str, r, r1, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
okbytearray(r2, st) ⊦ path∃(str, r, r1, putByteArray(bytes, r2, i, st)) ↔ path∃(str, r, r1, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]