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Proof step 5 from proof pathex-putbar (previous step)

¬ okbytearray(r2, putByteArray(bytes0, r2, i + 1, st)), okbytearray(r2, st), ∀ r2, st, str, r, r1, i. okbytearray(r2, st) → (path∃(str, r, r1, putByteArray(bytes0, r2, i, st)) ↔ path∃(str, r, r1, st)) ⊦ path∃(str, r, r1, putByteArray(bytes0, r2, i + 1, st)[r2 -- i ', byteval(by)]) ↔ path∃(str, r, r1, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
okbytearray(r2, st), ∀ r2, st, str, r, r1, i. okbytearray(r2, st) → (path∃(str, r, r1, putByteArray(bytes0, r2, i, st)) ↔ path∃(str, r, r1, st)) ⊦ path∃(str, r, r1, putByteArray(bytes0, r2, i + 1, st)[r2 -- i ', byteval(by)]) ↔ path∃(str, r, r1, st), okbytearray(r2, putByteArray(bytes0, r2, i + 1, st))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]