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Proof step 12 from proof pathex-putbyte (previous step)

∃ refs. refs ≠ [] ∧ refs .first = r ∧ refs .last = r0 ∧ validrefs(str, refs, st[refs .first -- _type] .type, st), okbytearray(r1, st) ⊦ ∃ refs. refs ≠ [] ∧ refs .first = r ∧ refs .last = r0 ∧ validrefs(str, refs, st[refs .first -- _type] .type, st[r1 -- i ', byteval(by)])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
validrefs(str, refs, st[refs .first -- _type] .type, st), okbytearray(r1, st) ⊦ refs = [], ∃ refs0. refs0 ≠ [] ∧ refs0 .first = refs .first ∧ refs0 .last = refs .last ∧ validrefs(str, refs0, st[refs0 .first -- _type] .type, st[r1 -- i ', byteval(by)])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]