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Proof step 2 from proof pathex-subset-01 (previous step)

st ⊆ st0, validref(str, r, ty, st), path∃(str, r, r1, st) ⊦ path∃(str, r, r1, st0)

User applied rule insert lemma

And obtained the following new goals

Proof step 1:
⊦ validref(str, r, ty, st) ∧ path∃(str, r, r1, st) ∧ st ⊆ st0 → path∃(str, r, r1, st0)

Rule argument

[LEMMAARG : pathex-subset, [str, r, ty, st, r1, st0] → [str, r, ty, st, r1, st0]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (str, r, ty, st, r1, st0)]]