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Proof step 4 from proof pathex-subset-02 (previous step)

¬ (validref(str, r, st[r -- _type] .type, st) ∧ path∃(str, r, r1, st) ∧ st ⊆ st0), st ⊆ st0, path∃(str, r, r1, st) ⊦ junkref(str, r, st), path∃(str, r, r1, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
st ⊆ st0, path∃(str, r, r1, st) ⊦ junkref(str, r, st), path∃(str, r, r1, st0), validref(str, r, st[r -- _type] .type, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]