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Proof step 10 from proof pathex-subset-equiv (previous step)

st ⊆ st0, validrefs(str, r ' + refs0, mkclasstype(`java.lang.Object' .class), st0) ⊦ refs0 = [], junkref(str, r, st), ∃ refs. refs ≠ [] ∧ refs .first = r ∧ refs .last = refs0 .last ∧ validrefs(str, refs, mkclasstype(`java.lang.Object' .class), st)

User applied rule exists right

And obtained the following new goals

Proof step 9:
st ⊆ st0, validrefs(str, r ' + refs0, mkclasstype(`java.lang.Object' .class), st0) ⊦ refs0 = [], junkref(str, r, st), r ' + refs0 ≠ [] ∧ (r ' + refs0) .first = r ∧ (r ' + refs0) .last = refs0 .last ∧ validrefs(str, r ' + refs0, mkclasstype(`java.lang.Object' .class), st)

Rule argument

[EXRARG : pos: right 3, [extquanttermlist: (r ' + refs0) abort:F , discard:T , computed:F ]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r ' + refs0)]]