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Proof step 19 from proof pathex-subset-equiv (previous step)

path∃(str, r, r0, st), st ⊆ st0 ⊦ path∃(str, r, r0, st0), junkref(str, r, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

[crewrite-arg: pathex-subset-02 , F , [str, r, st, r1, st0] → [str, r, st, r0, st0] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (str, r, st, r0, st0)]]