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Proof step 32 from proof validrefs-addobj-junkref (previous step)

0 < st[r1 -- _length] .intval, 0 ≤ i, validrefs(str, st[r1 -- i '] .refval ' + refs, st[r1 -- _type] .type .type, addobj(r, class, fis, st)), is_referencevalue(st[r1 -- i ']), i < st[r1 -- _length] .intval, st[r1 -- _type] .type ≤ ty0, newref(r, st), is_array(str, r1, st), ∀ str0, ty, r0, class0, fis0, st0. validrefs(str0, st[r1 -- i '] .refval ' + refs, ty, addobj(r0, class0, fis0, st0)) ∧ newref(r0, st0) ∧ (r0 = st[r1 -- i '] .refval ∨ r0 ∈ refs) → junkref(str0, st[r1 -- i '] .refval, st0) ⊦ r = r1, r = jvmref, r1 = jvmref, junkref(str, r1, st), r ≠ st[r1 -- i '] .refval ∧ ¬ r ∈ refs

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 31:
st[r1 -- i '] = refval(r2), 0 < st[r1 -- _length] .intval, 0 ≤ i, validrefs(str, r2 ' + refs, st[r1 -- _type] .type .type, addobj(r, class, fis, st)), is_referencevalue(st[r1 -- i ']), i < st[r1 -- _length] .intval, st[r1 -- _type] .type ≤ ty0, newref(r, st), is_array(str, r1, st), ∀ str0, ty, r0, class0, fis0, st0. validrefs(str0, r2 ' + refs, ty, addobj(r0, class0, fis0, st0)) ∧ newref(r0, st0) ∧ (r0 = r2 ∨ r0 ∈ refs) → junkref(str0, r2, st0) ⊦ r = r1, r = jvmref, r1 = jvmref, junkref(str, r1, st), r ≠ r2 ∧ ¬ r ∈ refs

Rule argument

[speclemmaarg: ,is_referencevalue(val) → (r = val .refval ↔ val = refval(r)) ,[val, r] → [st[r1 -- i '], r2] ,T ,javavalue , ,elim-13 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_referencevalue(val) → ( r = val .refval ↔ val = refval(r))])], [EXTRATERMS : (st[r1 -- i '], r2)]]