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Proof step 3 from proof validrefs-append-01 (previous step)

refs = refs0 + r ', validrefs(str, refs, ty, st), validrefs(str, r ' + refs1, ty0, st) ⊦ refs = [], validrefs(str, refs + refs1, ty, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
validrefs(str, refs0 + r ', ty, st), validrefs(str, r ' + refs1, ty0, st) ⊦ validrefs(str, (refs0 + r ') + refs1, ty, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ refs + r ' ≠ []])]]