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Proof step 6 from proof validrefs-applast-array (previous step)

st[r -- i '] = refval(r0), 0 < st[r -- _length] .intval, 0 ≤ i, type∃(str, st[r0 -- _type] .type), is_valid_ref(str, r0, st), st[r0 -- _type] .type ≤ st[r -- _type] .type .type, i < st[r -- _length] .intval, is_array(str, r, st), validrefs(str, refs + r ', ty, st) ⊦ validrefs(str, refs + r ' + r0 ', ty, st), ∃ i0. ¬ i0 < 0 ∧ ¬ st[r -- _length] .intval ≤ i0 ∧ is_referencevalue(st[r -- i0 ']) ∧ r0 = st[r -- i0 '] .refval ∧ validrefs(str, st[r -- i0 '] .refval ', st[r -- _type] .type .type, st)

User applied rule exists right

And obtained the following new goals

Proof step 5:
st[r -- i '] = refval(r0), 0 < st[r -- _length] .intval, 0 ≤ i, type∃(str, st[r0 -- _type] .type), is_valid_ref(str, r0, st), st[r0 -- _type] .type ≤ st[r -- _type] .type .type, i < st[r -- _length] .intval, is_array(str, r, st), validrefs(str, refs + r ', ty, st) ⊦ validrefs(str, refs + r ' + r0 ', ty, st), ¬ i < 0 ∧ ¬ st[r -- _length] .intval ≤ i ∧ is_referencevalue(st[r -- i ']) ∧ r0 = st[r -- i '] .refval ∧ validrefs(str, st[r -- i '] .refval ', st[r -- _type] .type .type, st)

Rule argument

[EXRARG : pos: right 2, [extquanttermlist: (i)abort:F, discard:T, computed:T]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (i)]]