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Proof step 44 from proof validrefs-contains-null (previous step)

∀ str, refs0, ty, st. validrefs(str, acc + jvmref ' + refs0, ty, st) → validrefs(str, acc + jvmref ', ty, st) ∧ refs0 = [], validrefs(str, (r + acc) + jvmref ' + refs0, ty, st) ⊦ validrefs(str, (r + acc) + jvmref ', ty, st) ∧ refs0 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 43:
validrefs(str, (r ' + acc) + jvmref ' + refs0, ty, st), ∀ str, refs0, ty, st. validrefs(str, acc + jvmref ' + refs0, ty, st) → validrefs(str, acc + jvmref ', ty, st) ∧ refs0 = [] ⊦ validrefs(str, (r ' + acc) + jvmref ', ty, st) ∧ refs0 = []

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r + refs = r ' + refs])]]