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Proof step 38 from proof validrefs-del-junkrefs (previous step)

0 < st[r0 -- _length] .intval, 0 ≤ i, junkrefs(str, st[r0 -- i '] .refval ', st[r0 -- _type] .type .type, st -- st[r0 -- i '] .refval), is_referencevalue(st[r0 -- i ']), i < st[r0 -- _length] .intval, is_array(str, r0, st), st[r0 -- _type] .type ≤ ty ⊦ st[r0 -- i '] .refval = r0, r0 = jvmref, junkref(str, r0, st), validrefs(str, r0 ' + st[r0 -- i '] .refval ', ty, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 37:
st[r0 -- i '] = refval(r), 0 < st[r0 -- _length] .intval, 0 ≤ i, junkrefs(str, r ', st[r0 -- _type] .type .type, st -- r), is_referencevalue(st[r0 -- i ']), i < st[r0 -- _length] .intval, is_array(str, r0, st), st[r0 -- _type] .type ≤ ty ⊦ r = r0, r0 = jvmref, junkref(str, r0, st), validrefs(str, r0 ' + r ', ty, st)

Rule argument

[speclemmaarg: ,is_referencevalue(val) → (r = val .refval ↔ val = refval(r)) ,[val, r] → [st[r0 -- i '], r] ,T ,javavalue , ,elim-13 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_referencevalue(val) → ( r = val .refval ↔ val = refval(r))])], [EXTRATERMS : (st[r0 -- i '], r)]]