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Proof step 6 from proof validrefs-delete-01 (conclusion)

⊦ ¬ validrefs(str, refs, ty0, st) ∧ ty ≤ ty0 → ¬ validrefs(str, refs, ty, st -- r)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
ty ≤ ty0, validrefs(str, refs, ty, st -- r) ⊦ validrefs(str, refs, ty0, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]