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Proof step 12 from proof validrefs-has-null (previous step)

acc = r0 + refs1 ∧ acc ≠ [], r0 = st[r -- fs '] .refval, is_obj(str, r, st), jvmref ∈ acc, st[r -- _type] .type ≤ ty, fs ' ∈ instfields(st[r -- _type] .type .class), is_referencevalue(st[r -- fs ']), validrefs(str, acc + refs0, fs .type, st), ∀ refs, str0, ty0, st0. refs ≠ [] → ¬ validrefs(str0, acc + refs, ty0, st0) ⊦ r = jvmref, refs0 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
is_obj(str, r, st), st[r -- _type] .type ≤ ty, fs ' ∈ instfields(st[r -- _type] .type .class), is_referencevalue(st[r -- fs ']), validrefs(str, (st[r -- fs '] .refval ' + refs1) + refs0, fs .type, st), ∀ refs, str0, ty0, st0. refs ≠ [] → ¬ validrefs(str0, (st[r -- fs '] .refval ' + refs1) + refs, ty0, st0) ⊦ r = jvmref, refs0 = [], jvmref ≠ st[r -- fs '] .refval ∧ ¬ jvmref ∈ refs1

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r ∈ r0 ' ↔ r = r0], [CSIMPSEQ : ⊦ r ∈ refs + refs0 ↔ ¬ ¬ (r ∈ refs ∨ r ∈ refs0)], [CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ r ' + refs ≠ []], [CSIMPSEQ : ⊦ r + refs = r ' + refs])]]