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Proof step 14 from proof validrefs-has-null (previous step)

is_obj(str, r, st) ∧ st[r -- _type] .type ≤ ty, is_obj(str, r, st), jvmref ∈ acc, acc + refs0 = [] ∨ (∃ fs. fs ' ∈ instfields(st[r -- _type] .type .class) ∧ is_referencevalue(st[r -- fs ']) ∧ (acc + refs0) .first = st[r -- fs '] .refval ∧ validrefs(str, acc + refs0, fs .type, st)), st[r -- _type] .type ≤ ty, ∀ refs, str0, ty0, st0. refs ≠ [] → ¬ validrefs(str0, acc + refs, ty0, st0) ⊦ r = jvmref, refs0 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
acc .first = st[r -- fs '] .refval, is_obj(str, r, st), jvmref ∈ acc, st[r -- _type] .type ≤ ty, fs ' ∈ instfields(st[r -- _type] .type .class), is_referencevalue(st[r -- fs ']), validrefs(str, acc + refs0, fs .type, st), ∀ refs, str0, ty0, st0. refs ≠ [] → ¬ validrefs(str0, acc + refs, ty0, st0) ⊦ r = jvmref, refs0 = []

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r ∈ refs → (refs + refs0) .first = refs .first], [CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ ¬ refs + refs0 ≠ [] ↔ refs = [] ∧ refs0 = []])]]