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Proof step 64 from proof validrefs-junkrefs-01 (conclusion)

⊦ junkrefs(str, refs + refs0, ty, st) ∧ ¬ junkrefs(str, refs, ty, st) → validrefs(str, refs, ty, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 63:
junkrefs(str, refs + refs0, ty, st) ⊦ junkrefs(str, refs, ty, st), validrefs(str, refs, ty, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]