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Proof step 42 from proof validrefs-junkrefs-append (conclusion)

⊦ validrefs(str, refs, ty, st) ∧ junkrefs(str, refs0, st[refs0 .first -- _type] .type, st) ∧ refs .last = refs0 .first ∧ refs0 ≠ [] ∧ refs ≠ [] → junkrefs(str, refs + refs0 .rest, ty, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 41:
refs .last = refs0 .first, junkrefs(str, refs0, st[refs0 .first -- _type] .type, st), validrefs(str, refs, ty, st) ⊦ refs0 = [], refs = [], junkrefs(str, refs + refs0 .rest, ty, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]