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Proof step 106 from proof validrefs-lastelem (previous step)

acc + r ' = r1 ' + refs, st[r0 -- i '] = refval(r1), is_array(str, r0, st), st[r0 -- _type] .type ≤ ty, i < st[r0 -- _length] .intval, validrefs(str, r1 ' + refs, st[r0 -- _type] .type .type, st), 0 ≤ i, 0 < st[r0 -- _length] .intval, validrefs(str, acc, st[r0 -- _type] .type .type, st) ∧ validrefs(str, acc + r ', st[r0 -- _type] .type .type, st) → acc = [] ∨ has_reffield(acc .last, st), acc = [] ∨ 0 ≤ i0 ∧ i0 < st[r0 -- _length] .intval ∧ is_referencevalue(st[r0 -- i0 ']) ∧ acc .first = st[r0 -- i0 '] .refval ∧ validrefs(str, acc, st[r0 -- _type] .type .type, st) ⊦ r0 = jvmref, has_reffield((r0 ' + acc) .last, st), r ≠ r1 ∧ ¬ r ∈ refs, ¬ r1 ∈ acc ∧ r1 ≠ r

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 105:
st[r0 -- i '] = refval(r1), acc + r ' = r1 ' + refs, 0 < st[r0 -- _length] .intval, 0 ≤ i, validrefs(str, r1 ' + refs, st[r0 -- _type] .type .type, st), i < st[r0 -- _length] .intval, st[r0 -- _type] .type ≤ ty, is_array(str, r0, st), acc = [] ∨ 0 ≤ i0 ∧ i0 < st[r0 -- _length] .intval ∧ is_referencevalue(st[r0 -- i0 ']) ∧ acc .first = st[r0 -- i0 '] .refval ∧ validrefs(str, acc, st[r0 -- _type] .type .type, st), validrefs(str, acc, st[r0 -- _type] .type .type, st) → acc = [] ∨ has_reffield(acc .last, st) ⊦ r0 = jvmref, has_reffield((r0 ' + acc) .last, st), ¬ r1 ∈ acc ∧ r1 ≠ r, r ≠ r1 ∧ ¬ r ∈ refs

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]