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Proof step 58 from proof validrefs-levelsubset-01 (previous step)

∀ str, str0, ty0, st, ty. level⊆(str, str0) ∧ validrefs(str0, refs0, ty0, st) ∧ validref(str, refs0 .first, ty, st) → validrefs(str, refs0, ty0, st) ⊦ level⊆(str, str0) ∧ validrefs(str0, r + refs0, ty0, st) ∧ validref(str, (r + refs0) .first, ty, st) → validrefs(str, r + refs0, ty0, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 57:
level⊆(str, str0), validrefs(str0, r ' + refs0, ty0, st), validref(str, r, ty, st), ∀ str, str0, ty0, st, ty. level⊆(str, str0) ∧ validrefs(str0, refs0, ty0, st) ∧ validref(str, refs0 .first, ty, st) → validrefs(str, refs0, ty0, st) ⊦ validrefs(str, r ' + refs0, ty0, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : list, references, a, ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPNAMEDSEQ : list, references, c-08, ⊦ (r ' + refs) .first = r], [CSIMPNAMEDSEQ : list, references, c, ⊦ r + refs = r ' + refs])]]