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Proof step 37 from proof validrefs-levelsubset (conclusion)

⊦ level⊆(str, str0) ∧ validrefs(str, refs, ty0, st) → validrefs(str0, refs, ty0, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 36:
validrefs(str, refs, ty0, st), level⊆(str, str0) ⊦ validrefs(str0, refs, ty0, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]