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Proof step 19 from proof validrefs-maxlen (previous step)

acc .first = st[r -- fs '] .refval, is_obj(str, r, st), # st .refs < # acc, st[r -- _type] .type ≤ ty, fs ' ∈ instfields(st[r -- _type] .type .class), is_referencevalue(st[r -- fs ']), validrefs(str, acc, fs .type, st), ∀ str0, ty0, st0. validrefs(str0, acc, ty0, st0) → # acc ≤ # st0 .refs + 1 ⊦ r = jvmref, acc = [], dups(acc), r ∈ acc

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 18:
acc = r0 + refs, r0 = st[r -- fs '] .refval, is_obj(str, r, st), # st .refs < # acc, st[r -- _type] .type ≤ ty, fs ' ∈ instfields(st[r -- _type] .type .class), is_referencevalue(st[r -- fs ']), validrefs(str, acc, fs .type, st), ∀ str0, ty0, st0. validrefs(str0, acc, ty0, st0) → # acc ≤ # st0 .refs + 1 ⊦ r = jvmref, acc = [], dups(acc), r ∈ acc

Rule argument

[speclemmaarg: refs ≠ [] ,r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0 ,[refs, r, refs0] → [acc, r0, refs] ,T ,list-data ,references-olista ,elim-list-c ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : refs ≠ [] ⊦ r = refs .first ∧ refs0 = refs .rest ↔ refs = r + refs0])], [EXTRATERMS : (acc, r0, refs)]]