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Proof step 20 from proof validrefs-nodups (previous step)

refs2 .last = jvmref, ∃ refs0, refs1. refs2 = refs0 + (r + refs1), validrefs(str, r ' + refs2, ty, st), ∀ st, ty, str, refs0. # refs0 < # (r + refs2) → ( validrefs(str, refs0, ty, st) ∧ refs0 ≠ [] ∧ refs0 .last = jvmref → (∃ refs1. validrefs(str, refs1, ty, st) ∧ refs1 ≠ [] ∧ refs1 .last = jvmref ∧ refs0 .first = refs1 .first ∧ ¬ dups(refs1) ∧ refs1 ⊆ refs0)) ⊦ refs2 = [], ∃ refs. validrefs(str, refs, ty, st) ∧ refs ≠ [] ∧ refs .last = jvmref ∧ r = refs .first ∧ ¬ dups(refs) ∧ refs ⊆ refs .first ' + refs2

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
(r ' + refs) .last = jvmref, validrefs(str, r ' + refs0 + r ' + refs, ty, st), ∀ st, ty, str, refs1. # refs1 < # (r + (refs0 + (r + refs))) → ( validrefs(str, refs1, ty, st) ∧ refs1 ≠ [] ∧ refs1 .last = jvmref → (∃ refs3. validrefs(str, refs3, ty, st) ∧ refs3 ≠ [] ∧ refs3 .last = jvmref ∧ refs1 .first = refs3 .first ∧ ¬ dups(refs3) ∧ refs3 ⊆ refs1)) ⊦ ∃ refs1. validrefs(str, refs1, ty, st) ∧ refs1 ≠ [] ∧ refs1 .last = jvmref ∧ r = refs1 .first ∧ ¬ dups(refs1) ∧ refs1 ⊆ refs1 .first ' + refs0 + refs1 .first ' + refs

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ refs + r ' + refs0 ≠ []], [CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ (refs + r ' + refs0) .last = (r ' + refs0) .last], [CSIMPSEQ : ⊦ r + refs = r ' + refs])]]