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Proof step 34 from proof validrefs-nodups (previous step)

refs .last = jvmref, (r ' + refs4) .last = jvmref, validrefs(str, (r ' + refs1) + r0 ' + refs, ty, st), validrefs(str, r ' + refs1 + r0 ' + refs0 + r0 ' + refs, ty, st), refs4 ⊆ (r ' + refs1) + r0 ' + refs, validrefs(str, r ' + refs4, ty, st), ∀ st, ty, str, refs3. # refs3 < # (r + (refs1 + (r0 + (refs0 + (r0 + refs))))) → ( validrefs(str, refs3, ty, st) ∧ refs3 ≠ [] ∧ refs3 .last = jvmref → (∃ refs1. validrefs(str, refs1, ty, st) ∧ refs1 ≠ [] ∧ refs1 .last = jvmref ∧ refs3 .first = refs1 .first ∧ ¬ dups(refs1) ∧ refs1 ⊆ refs3)) ⊦ refs4 = [], r = r0, refs = [], r ∈ refs1, r ∈ refs0, r ∈ refs, dups(refs4), r ∈ refs4, ∃ refs3. validrefs(str, refs3, ty, st) ∧ refs3 ≠ [] ∧ refs3 .last = jvmref ∧ r = refs3 .first ∧ ¬ dups(refs3) ∧ refs3 ⊆ refs3 .first ' + refs1 + r0 ' + refs0 + r0 ' + refs

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ refs ≠ [] → (r ' + refs) .last = refs .last])]]