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Proof step 9 from proof validrefs-nopathex (previous step)

validrefs(str, r ' + refs1 + r0 ' + refs0, ty, st), validrefs(str, r ' + refs1 + r0 ' + refs0, st[r -- _type] .type, st) ⊦ r0 ∈ refs1, ∃ refs0. refs0 ≠ [] ∧ refs0 .first = r ∧ refs0 .last = r0 ∧ validrefs(str, refs0, st[refs0 .first -- _type] .type, st)

User applied rule exists right

And obtained the following new goals

Proof step 8:
validrefs(str, r ' + refs1 + r0 ' + refs0, ty, st), validrefs(str, r ' + refs1 + r0 ' + refs0, st[r -- _type] .type, st) ⊦ r0 ∈ refs1, r ' + refs1 + r0 ' ≠ [] ∧ (r ' + refs1 + r0 ') .first = r ∧ (r ' + refs1 + r0 ') .last = r0 ∧ validrefs(str, r ' + refs1 + r0 ', st[(r ' + refs1 + r0 ') .first -- _type] .type, st)

Rule argument

[EXRARG : pos: right 2, [extquanttermlist: (r ' + refs1 + r0 ') abort:F , discard:T , computed:F ]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r ' + refs1 + r0 ')]]