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Proof step 5 from proof validrefs-not (conclusion)

⊦ ¬ is_valid_ref(str, r, st) → (validrefs(str, r ' + refs, ty, st) ↔ r = jvmref ∧ refs = [])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ validrefs(str, jvmref ', ty, st)
Proof step 4:
validrefs(str, r ' + refs, ty, st) ⊦ is_valid_ref(str, r, st), r = jvmref ∧ refs = []

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ refs + [] = refs])]]