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Proof step 31 from proof validrefs-prefix (previous step)

is_array(str, r, st) ∧ st[r -- _type] .type ≤ ty, is_array(str, r, st), acc + refs0 = [] ∨ (∃ i. 0 ≤ i ∧ i < st[r -- _length] .intval ∧ is_referencevalue(st[r -- i ']) ∧ (acc + refs0) .first = st[r -- i '] .refval ∧ validrefs(str, acc + refs0, st[r -- _type] .type .type, st)), st[r -- _type] .type ≤ ty, ∀ str, refs0, ty, st. validrefs(str, acc + refs0, ty, st) → validrefs(str, acc, ty, st) ⊦ r = jvmref, validrefs(str, r ' + acc, ty, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 30:
is_array(str, r, st), st[r -- _type] .type ≤ ty, ∀ str, refs0, ty, st. validrefs(str, acc + refs0, ty, st) → validrefs(str, acc, ty, st), acc = [] ∧ refs0 = [] ∨ 0 ≤ i ∧ i < st[r -- _length] .intval ∧ is_referencevalue(st[r -- i ']) ∧ (acc + refs0) .first = st[r -- i '] .refval ∧ validrefs(str, acc + refs0, st[r -- _type] .type .type, st) ⊦ r = jvmref, validrefs(str, r ' + acc, ty, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (refs + refs0) + refs1 = refs + refs0 + refs1], [CSIMPSEQ : ⊦ ¬ refs + refs0 ≠ [] ↔ refs = [] ∧ refs0 = []])]]