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Proof step 21 from proof validrefs-put-notin-03 (previous step)

∃ fs. fs ' ∈ instfields(st[r -- _type] .type .class) ∧ is_referencevalue(st[r -- sk, val][r -- fs ']) ∧ r0 = (st[r -- sk, val][r -- fs ']) .refval ∧ validrefs(str, (st[r -- sk, val][r -- fs ']) .refval ' + refs1, fs .type, st[r -- sk, val]), is_obj(str, r, st), is_valid_ref(r, st), is_obj(str, r, st[r -- sk, val]), st[r -- _type] .type ≤ ty ⊦ ∃ fs. fs ' ∈ instfields(st[r -- _type] .type .class) ∧ is_referencevalue(st[r -- fs ']) ∧ r0 = st[r -- fs '] .refval ∧ validrefs(str, st[r -- fs '] .refval ' + refs1, fs .type, st), sk = _length, sk = _type, r0 = st[r -- sk] .refval, val .refval = r0, r = r0, r = jvmref, r0 ∈ refs1, dups(refs1), r ∈ refs1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
fs ' ∈ instfields(st[r -- _type] .type .class), is_referencevalue(st[r -- sk, val][r -- fs ']), validrefs(str, (st[r -- sk, val][r -- fs ']) .refval ' + refs1, fs .type, st[r -- sk, val]), is_obj(str, r, st), is_valid_ref(r, st), is_obj(str, r, st[r -- sk, val]), st[r -- _type] .type ≤ ty ⊦ sk = _length, sk = _type, (st[r -- sk, val][r -- fs ']) .refval = st[r -- sk] .refval, val .refval = (st[r -- sk, val][r -- fs ']) .refval, r = (st[r -- sk, val][r -- fs ']) .refval, r = jvmref, (st[r -- sk, val][r -- fs ']) .refval ∈ refs1, dups(refs1), r ∈ refs1, ∃ fs0. fs0 ' ∈ instfields(st[r -- _type] .type .class) ∧ is_referencevalue(st[r -- fs0 ']) ∧ (st[r -- sk, val][r -- fs ']) .refval = st[r -- fs0 '] .refval ∧ validrefs(str, st[r -- fs0 '] .refval ' + refs1, fs0 .type, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]